Optimal. Leaf size=161 \[ -\frac{2 b^2 n^2 \text{PolyLog}\left (2,-\frac{e x}{d}\right )}{3 d e^3}+\frac{b n x \left (2 a+2 b \log \left (c x^n\right )+b n\right )}{3 d e^2 (d+e x)}-\frac{b n \log \left (\frac{e x}{d}+1\right ) \left (2 a+2 b \log \left (c x^n\right )+3 b n\right )}{3 d e^3}+\frac{x^3 \left (a+b \log \left (c x^n\right )\right )^2}{3 d (d+e x)^3}+\frac{b n x^2 \left (a+b \log \left (c x^n\right )\right )}{3 d e (d+e x)^2} \]
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Rubi [A] time = 0.715541, antiderivative size = 274, normalized size of antiderivative = 1.7, number of steps used = 25, number of rules used = 11, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.478, Rules used = {2353, 2319, 2347, 2344, 2301, 2317, 2391, 2314, 31, 44, 2318} \[ -\frac{2 b^2 n^2 \text{PolyLog}\left (2,-\frac{e x}{d}\right )}{3 d e^3}-\frac{d^2 \left (a+b \log \left (c x^n\right )\right )^2}{3 e^3 (d+e x)^3}+\frac{4 b n x \left (a+b \log \left (c x^n\right )\right )}{3 d e^2 (d+e x)}+\frac{b d n \left (a+b \log \left (c x^n\right )\right )}{3 e^3 (d+e x)^2}-\frac{2 b n \log \left (\frac{e x}{d}+1\right ) \left (a+b \log \left (c x^n\right )\right )}{3 d e^3}+\frac{x \left (a+b \log \left (c x^n\right )\right )^2}{d e^2 (d+e x)}+\frac{d \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)^2}-\frac{2 \left (a+b \log \left (c x^n\right )\right )^2}{3 d e^3}-\frac{b^2 n^2}{3 e^3 (d+e x)}-\frac{b^2 n^2 \log (x)}{3 d e^3}-\frac{b^2 n^2 \log (d+e x)}{d e^3} \]
Antiderivative was successfully verified.
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Rule 2353
Rule 2319
Rule 2347
Rule 2344
Rule 2301
Rule 2317
Rule 2391
Rule 2314
Rule 31
Rule 44
Rule 2318
Rubi steps
\begin{align*} \int \frac{x^2 \left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^4} \, dx &=\int \left (\frac{d^2 \left (a+b \log \left (c x^n\right )\right )^2}{e^2 (d+e x)^4}-\frac{2 d \left (a+b \log \left (c x^n\right )\right )^2}{e^2 (d+e x)^3}+\frac{\left (a+b \log \left (c x^n\right )\right )^2}{e^2 (d+e x)^2}\right ) \, dx\\ &=\frac{\int \frac{\left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^2} \, dx}{e^2}-\frac{(2 d) \int \frac{\left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^3} \, dx}{e^2}+\frac{d^2 \int \frac{\left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^4} \, dx}{e^2}\\ &=-\frac{d^2 \left (a+b \log \left (c x^n\right )\right )^2}{3 e^3 (d+e x)^3}+\frac{d \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)^2}+\frac{x \left (a+b \log \left (c x^n\right )\right )^2}{d e^2 (d+e x)}-\frac{(2 b d n) \int \frac{a+b \log \left (c x^n\right )}{x (d+e x)^2} \, dx}{e^3}+\frac{\left (2 b d^2 n\right ) \int \frac{a+b \log \left (c x^n\right )}{x (d+e x)^3} \, dx}{3 e^3}-\frac{(2 b n) \int \frac{a+b \log \left (c x^n\right )}{d+e x} \, dx}{d e^2}\\ &=-\frac{d^2 \left (a+b \log \left (c x^n\right )\right )^2}{3 e^3 (d+e x)^3}+\frac{d \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)^2}+\frac{x \left (a+b \log \left (c x^n\right )\right )^2}{d e^2 (d+e x)}-\frac{2 b n \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac{e x}{d}\right )}{d e^3}-\frac{(2 b n) \int \frac{a+b \log \left (c x^n\right )}{x (d+e x)} \, dx}{e^3}+\frac{(2 b d n) \int \frac{a+b \log \left (c x^n\right )}{x (d+e x)^2} \, dx}{3 e^3}+\frac{(2 b n) \int \frac{a+b \log \left (c x^n\right )}{(d+e x)^2} \, dx}{e^2}-\frac{(2 b d n) \int \frac{a+b \log \left (c x^n\right )}{(d+e x)^3} \, dx}{3 e^2}+\frac{\left (2 b^2 n^2\right ) \int \frac{\log \left (1+\frac{e x}{d}\right )}{x} \, dx}{d e^3}\\ &=\frac{b d n \left (a+b \log \left (c x^n\right )\right )}{3 e^3 (d+e x)^2}+\frac{2 b n x \left (a+b \log \left (c x^n\right )\right )}{d e^2 (d+e x)}-\frac{d^2 \left (a+b \log \left (c x^n\right )\right )^2}{3 e^3 (d+e x)^3}+\frac{d \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)^2}+\frac{x \left (a+b \log \left (c x^n\right )\right )^2}{d e^2 (d+e x)}-\frac{2 b n \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac{e x}{d}\right )}{d e^3}-\frac{2 b^2 n^2 \text{Li}_2\left (-\frac{e x}{d}\right )}{d e^3}+\frac{(2 b n) \int \frac{a+b \log \left (c x^n\right )}{x (d+e x)} \, dx}{3 e^3}-\frac{(2 b n) \int \frac{a+b \log \left (c x^n\right )}{x} \, dx}{d e^3}-\frac{(2 b n) \int \frac{a+b \log \left (c x^n\right )}{(d+e x)^2} \, dx}{3 e^2}+\frac{(2 b n) \int \frac{a+b \log \left (c x^n\right )}{d+e x} \, dx}{d e^2}-\frac{\left (b^2 d n^2\right ) \int \frac{1}{x (d+e x)^2} \, dx}{3 e^3}-\frac{\left (2 b^2 n^2\right ) \int \frac{1}{d+e x} \, dx}{d e^2}\\ &=\frac{b d n \left (a+b \log \left (c x^n\right )\right )}{3 e^3 (d+e x)^2}+\frac{4 b n x \left (a+b \log \left (c x^n\right )\right )}{3 d e^2 (d+e x)}-\frac{\left (a+b \log \left (c x^n\right )\right )^2}{d e^3}-\frac{d^2 \left (a+b \log \left (c x^n\right )\right )^2}{3 e^3 (d+e x)^3}+\frac{d \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)^2}+\frac{x \left (a+b \log \left (c x^n\right )\right )^2}{d e^2 (d+e x)}-\frac{2 b^2 n^2 \log (d+e x)}{d e^3}-\frac{2 b^2 n^2 \text{Li}_2\left (-\frac{e x}{d}\right )}{d e^3}+\frac{(2 b n) \int \frac{a+b \log \left (c x^n\right )}{x} \, dx}{3 d e^3}-\frac{(2 b n) \int \frac{a+b \log \left (c x^n\right )}{d+e x} \, dx}{3 d e^2}-\frac{\left (2 b^2 n^2\right ) \int \frac{\log \left (1+\frac{e x}{d}\right )}{x} \, dx}{d e^3}-\frac{\left (b^2 d n^2\right ) \int \left (\frac{1}{d^2 x}-\frac{e}{d (d+e x)^2}-\frac{e}{d^2 (d+e x)}\right ) \, dx}{3 e^3}+\frac{\left (2 b^2 n^2\right ) \int \frac{1}{d+e x} \, dx}{3 d e^2}\\ &=-\frac{b^2 n^2}{3 e^3 (d+e x)}-\frac{b^2 n^2 \log (x)}{3 d e^3}+\frac{b d n \left (a+b \log \left (c x^n\right )\right )}{3 e^3 (d+e x)^2}+\frac{4 b n x \left (a+b \log \left (c x^n\right )\right )}{3 d e^2 (d+e x)}-\frac{2 \left (a+b \log \left (c x^n\right )\right )^2}{3 d e^3}-\frac{d^2 \left (a+b \log \left (c x^n\right )\right )^2}{3 e^3 (d+e x)^3}+\frac{d \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)^2}+\frac{x \left (a+b \log \left (c x^n\right )\right )^2}{d e^2 (d+e x)}-\frac{b^2 n^2 \log (d+e x)}{d e^3}-\frac{2 b n \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac{e x}{d}\right )}{3 d e^3}+\frac{\left (2 b^2 n^2\right ) \int \frac{\log \left (1+\frac{e x}{d}\right )}{x} \, dx}{3 d e^3}\\ &=-\frac{b^2 n^2}{3 e^3 (d+e x)}-\frac{b^2 n^2 \log (x)}{3 d e^3}+\frac{b d n \left (a+b \log \left (c x^n\right )\right )}{3 e^3 (d+e x)^2}+\frac{4 b n x \left (a+b \log \left (c x^n\right )\right )}{3 d e^2 (d+e x)}-\frac{2 \left (a+b \log \left (c x^n\right )\right )^2}{3 d e^3}-\frac{d^2 \left (a+b \log \left (c x^n\right )\right )^2}{3 e^3 (d+e x)^3}+\frac{d \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)^2}+\frac{x \left (a+b \log \left (c x^n\right )\right )^2}{d e^2 (d+e x)}-\frac{b^2 n^2 \log (d+e x)}{d e^3}-\frac{2 b n \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac{e x}{d}\right )}{3 d e^3}-\frac{2 b^2 n^2 \text{Li}_2\left (-\frac{e x}{d}\right )}{3 d e^3}\\ \end{align*}
Mathematica [B] time = 0.461637, size = 371, normalized size = 2.3 \[ -\frac{\frac{2 b^2 n^2 \text{PolyLog}\left (2,-\frac{e x}{d}\right )}{d}+\frac{a^2 d^2}{(d+e x)^3}+\frac{3 a^2}{d+e x}-\frac{3 a^2 d}{(d+e x)^2}-\frac{a^2}{d}+\frac{2 a b d^2 \log \left (c x^n\right )}{(d+e x)^3}+\frac{6 a b \log \left (c x^n\right )}{d+e x}-\frac{6 a b d \log \left (c x^n\right )}{(d+e x)^2}-\frac{2 a b \log \left (c x^n\right )}{d}+\frac{4 a b n}{d+e x}-\frac{a b d n}{(d+e x)^2}+\frac{2 a b n \log \left (\frac{e x}{d}+1\right )}{d}+\frac{b^2 d^2 \log ^2\left (c x^n\right )}{(d+e x)^3}+\frac{3 b^2 \log ^2\left (c x^n\right )}{d+e x}-\frac{3 b^2 d \log ^2\left (c x^n\right )}{(d+e x)^2}+\frac{4 b^2 n \log \left (c x^n\right )}{d+e x}-\frac{b^2 d n \log \left (c x^n\right )}{(d+e x)^2}+\frac{2 b^2 n \log \left (c x^n\right ) \log \left (\frac{e x}{d}+1\right )}{d}-\frac{b^2 \log ^2\left (c x^n\right )}{d}+\frac{b^2 n^2}{d+e x}+\frac{3 b^2 n^2 \log (d+e x)}{d}-\frac{3 b^2 n^2 \log (x)}{d}}{3 e^3} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.301, size = 1658, normalized size = 10.3 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{1}{3} \, a b n{\left (\frac{4 \, e x + 3 \, d}{e^{5} x^{2} + 2 \, d e^{4} x + d^{2} e^{3}} + \frac{2 \, \log \left (e x + d\right )}{d e^{3}} - \frac{2 \, \log \left (x\right )}{d e^{3}}\right )} - \frac{1}{3} \,{\left (\frac{{\left (3 \, e^{2} x^{2} + 3 \, d e x + d^{2}\right )} \log \left (x^{n}\right )^{2}}{e^{6} x^{3} + 3 \, d e^{5} x^{2} + 3 \, d^{2} e^{4} x + d^{3} e^{3}} - 3 \, \int \frac{3 \, e^{3} x^{3} \log \left (c\right )^{2} + 2 \,{\left (6 \, d e^{2} n x^{2} + 4 \, d^{2} e n x + d^{3} n + 3 \,{\left (e^{3} n + e^{3} \log \left (c\right )\right )} x^{3}\right )} \log \left (x^{n}\right )}{3 \,{\left (e^{7} x^{5} + 4 \, d e^{6} x^{4} + 6 \, d^{2} e^{5} x^{3} + 4 \, d^{3} e^{4} x^{2} + d^{4} e^{3} x\right )}}\,{d x}\right )} b^{2} - \frac{2 \,{\left (3 \, e^{2} x^{2} + 3 \, d e x + d^{2}\right )} a b \log \left (c x^{n}\right )}{3 \,{\left (e^{6} x^{3} + 3 \, d e^{5} x^{2} + 3 \, d^{2} e^{4} x + d^{3} e^{3}\right )}} - \frac{{\left (3 \, e^{2} x^{2} + 3 \, d e x + d^{2}\right )} a^{2}}{3 \,{\left (e^{6} x^{3} + 3 \, d e^{5} x^{2} + 3 \, d^{2} e^{4} x + d^{3} e^{3}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b^{2} x^{2} \log \left (c x^{n}\right )^{2} + 2 \, a b x^{2} \log \left (c x^{n}\right ) + a^{2} x^{2}}{e^{4} x^{4} + 4 \, d e^{3} x^{3} + 6 \, d^{2} e^{2} x^{2} + 4 \, d^{3} e x + d^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2} \left (a + b \log{\left (c x^{n} \right )}\right )^{2}}{\left (d + e x\right )^{4}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \log \left (c x^{n}\right ) + a\right )}^{2} x^{2}}{{\left (e x + d\right )}^{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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